I was literally up the whole night-

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Wait till you go to grade 11. That shit will tear you apart!

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Lmaoaoapaoaoaoao. But Iām pretty good at math tho

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The question says he wants to rent a car for 10 days. The first company charges a \$35 rental fee and \$110 for 3 days. If he wants it for 10 days, based on the rate, he would need to pay around \$366.67. Add 35 to that, and you get \$401.67.

Iām not sure if Iām reading this right.

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110=3x+35

Find for x it would be: 25

Sub it in

Y=25x+ 35 <- you sub in 10 your answe would be 285

Y= 28x + 15

Sub the 10 you get:

Y= 28(10)+15
Y=295

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i heard 11th grade was the hardest year :0

Since the first option is cheaper, obviously the first option LMAO Iām trying to do this while brushing my teeth

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Hang on. I read the problem that its \$35 plus \$110 per three days?
So the equation would be:

y = \$35 + ( (\$110/3) * 10)
Which means that Y = \$401.67?

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Its not bad if you have a good teacher. I had a great teacher and ended with an 87% average so its not that bad.

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Wait?
I thought you guys were done?

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Thatās what Iām thinking too.

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You canāt divide, youād have to multiply. For every 3 days itās 110

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We have conflicting answers. Some people say first company while some say second.

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He wants to rent for 10 days. So the first company would be more. You would divide 110 by 3 to see the rate for each day then multiply by 10.

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Haha Im in Geometry and thatās harder than Alegbra 1, im in 9th grade as well!

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I divided by 3 to get the cost PER DAY then multiplied by 10.

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No you donāt divide \$110 by 3 because that is your total amount and \$35 is included as well in the \$110

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You also cannot multiply 10 at the end because the that first equation only gives you the result for 3 days, so youāre basically saying 3 days plus 10 days

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I love how you added a math problem onto the forums.

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The question doesnāt say that it totals 110.

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